Problem proving if a limit exists

[Tomath]

Homework Statement

We are given two functions f : $\mathbb{R}^n$ -> $\mathbb{R}$ and g: $\mathbb{R}^n$ -> $\mathbb{R}$. For every x $\in$ $\mathbb{R}^n$ we define the following:

k(x) = max{f(x), g(x)}
h(x) = min{f(x), g(x)}

The question is:
if lim x-> a k(x) exists and lim x-> a h(x) exists, and the limits are equal, does that imply that lim x->a f(x) exists?

Homework Equations

The Attempt at a Solution

Suppose we define f(x) = 1/x and g(x) = x. At x = 0 f(x) is not defined, so g(x) is the minimum and the maximum at x = 0. Therefore k(x) = g(x) and h(x) = g(x). We know that lim x-> 0 h(x) exists and lim x-> 0 k(x) exists, but lim x -> 0 f(x) does not exists.

Is my work here correct or am i wrong in assuming that if f(0) is not defined then g(0) is the maximum and the minimum at x = 0?

 

[SammyS]

Homework Statement

We are given two functions f : $\mathbb{R}^n$ -> $\mathbb{R}$ and g: $\mathbb{R}^n$ -> $\mathbb{R}$. For every x $\in$ $\mathbb{R}^n$ we define the following:

k(x) = max{f(x), g(x)}
h(x) = min{f(x), g(x)}

The question is:
if lim x-> a k(x) exists and lim x-> a h(x) exists, and the limits are equal, does that imply that lim x->a f(x) exists?

Homework Equations

The Attempt at a Solution

Suppose we define f(x) = 1/x and g(x) = x. At x = 0 f(x) is not defined, so g(x) is the minimum and the maximum at x = 0. Therefore k(x) = g(x) and h(x) = g(x). We know that lim x-> 0 h(x) exists and lim x-> 0 k(x) exists, but lim x -> 0 f(x) does not exists.

Is my work here correct or am i wrong in assuming that if f(0) is not defined then g(0) is the maximum and the minimum at x = 0?

Hello Tomath. Welcome to PF !

lim _x→0 k(x) does not exist. Furthermore, this limit has nothing to do with whether or not k(0) exists, nor does it depend upon the value of k(x). From the left of x=0, k(x) approaches 0. From the right it approaches +∞ .