Problem with physics acceleration

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SUMMARY

The discussion centers on calculating the speed and distance of a car accelerating on wet pavement with a maximum acceleration of 0.20 g, equivalent to 1.96 m/s². The user initially struggled with the calculations but confirmed that using 9.8 m/s² for gravity is correct. After 2.0 seconds, the car reaches a speed of 3.9 m/s, and further calculations are needed to determine the distance traveled after 4.0 seconds.

PREREQUISITES
  • Understanding of basic physics concepts, specifically acceleration and gravity.
  • Familiarity with the formula for calculating speed: final speed = initial speed + (acceleration × time).
  • Knowledge of kinematic equations for distance: distance = initial speed × time + 0.5 × acceleration × time².
  • Basic arithmetic and algebra skills for solving equations.
NEXT STEPS
  • Review kinematic equations in physics for motion under constant acceleration.
  • Practice problems involving acceleration on different surfaces, such as wet pavement.
  • Explore the effects of friction on vehicle acceleration and stopping distances.
  • Learn about the implications of gravitational acceleration variations in different environments.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to acceleration and motion on different surfaces.

pdot
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' On wet pavement, a car can be accelerated with a maximum acceleration a = .20 g before its tires slip. '
a) starting from rest, how fast is it moving after 2.0s
b)how far has it moved after 4.0s

i have looked over this question plenty of times and have never got the right answer. i have looked at the answer key and found that it used ' 9.8m/s squared ' in the equation. is this right?
 
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pdot said:
' On wet pavement, a car can be accelerated with a maximum acceleration a = .20 g before its tires slip. '
a) starting from rest, how fast is it moving after 2.0s
b)how far has it moved after 4.0s

i have looked over this question plenty of times and have never got the right answer. i have looked at the answer key and found that it used ' 9.8m/s squared ' in the equation. is this right?
If an object accelerates at 1 g on Earth, it is accelerating at 9.8m/sec2, where g is the acceleration of gravity on Planet Earth. So a 0.20 g acceleration is 1.96 m/sec2
 


yeah i went to my physics class and found out that my teacher had missed that. i got (.2)(9.8)(2) = 3.9m/s
 

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