Problem with squares and roots

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Homework Help Overview

The discussion revolves around understanding the function f(x) = √(x+1)² - √(x-1)², particularly focusing on the implications of squares and roots in the context of the function's domain and behavior.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to simplify the function by removing the squares and roots, leading to an initial conclusion that is later questioned. Some participants highlight the importance of recognizing that √x² = |x|, prompting a reevaluation of the function.

Discussion Status

Participants are exploring different interpretations of the function based on its definition across various regions of x. Guidance has been provided regarding the absolute value and the implications for the function's behavior in different domains.

Contextual Notes

There is a discussion about the domain of the function, with some participants questioning the assumption that x must be non-negative, while others clarify that the domain is all real numbers.

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Homework Statement



Hi, I am currently studying for a exam and I have noticed I have difficulty with squares and roots. I decided to take a problem from an exam so that I can illustrate the problems I am having with it.

Homework Equations



If f(x) = √(x+1)2 - √(x-1)2

(a) f(x) = 2; (b) f(x) = 2x; (c) f(x) = 2√x; (d) none of (a)-(c).

The Attempt at a Solution



My first instict is to remove the squares and the roots so that f(x) = x+1 - (x-1) which in turn gives me the answer (a). This is incorrect. I am guessing it has to do with the fact that x is not defined to be ≥ 0. Any help?
 
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BruceSpringste said:
My first instict is to remove the squares and the roots so that f(x) = x+1 - (x-1) which in turn gives me the answer (a). This is incorrect.

Remember √x2 = |x| and not simply x.Now rewrite f(x) .

BruceSpringste said:
I am guessing it has to do with the fact that x is not defined to be ≥ 0. Any help?

No.The domain of the function is R .
 
Last edited:
Tanya Sharma said:
Remember √x2 = |x| and not simply x.

Now rewrite f(x) .

f(x) = |x+1| - |x-1|

I'm a bit slow, where do I take it from here?
 
Good...

Now the function will be defined differently in different regions.First consider x<-1

What is the value of |x+1| when x<-1 ?
What is the value of |x-1| when x<-1 ?
What is the value of |x+1|-|x+1|when x<-1 ?
 
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Alright now I understand completely! Thank you very much!
 

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