Problem with Vibration and Waves AP French?

  • Context: High School 
  • Thread starter Thread starter Karim Habashy
  • Start date Start date
  • Tags Tags
    Ap Vibration Waves
Click For Summary

Discussion Overview

The discussion revolves around the geometry of angles in a triangle related to vibrations and waves, specifically focusing on the angle COB and its relationship to other angles in the triangle OCB. Participants are examining the correctness of angle measurements and their implications in a geometric context.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant suggests that COB is 90 - δ instead of 90 - δ/2, seeking confirmation from others.
  • Another participant counters this claim, asserting that COB is indeed over 2, questioning the reasoning behind the initial assertion.
  • A third participant provides a calculation showing that ∠'COB' equals 90 - δ based on the triangle OCB, using the angles CBO and OCB.
  • Another participant challenges the assumption that CBO is 90, proposing that the triangles involved may be isosceles rather than right-angled, and questions the certainty of the angle OCB being δ.
  • A later reply acknowledges a misunderstanding regarding the geometry, indicating a shift in perspective after realizing the error in mental visualization.

Areas of Agreement / Disagreement

Participants express differing views on the measurements of angles, with no consensus reached on the correct interpretation of angle COB and its relationship to the other angles in the triangle.

Contextual Notes

Participants' arguments depend on their interpretations of geometric properties and relationships, with some assumptions about the nature of the triangles involved remaining unresolved.

Karim Habashy
Messages
31
Reaction score
1
Hi All,

Kindly see the attached Pictures.
Vectors.PNG
Equation.PNG


I think COB is not 90 - δ/2
But
COB is 90-δ

Can someone confirm.

Thanks.
 
Physics news on Phys.org
No. It is over 2.
Why do you think is not so?
 
∠'CBO' = 90 and ∠'OCB' = δ
∴ from the Δ 'OCB' we find that :
∠'COB' = 180-90-δ = 90-δ
 
Why do you think CBO is 90? These triangles seem to be isosceles and not right-angle. Aren't these triangles all equal?
Otherwise how do you know that the angle at OCB is delta?
 
Ya, you r right, i got it -_- .
My mind played tricks on me, i had the wrong mental image of an inscribed polygon in a circle, haven't done geometry in sometime.

Thanks
 

Similar threads

  • · Replies 41 ·
2
Replies
41
Views
17K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 21 ·
Replies
21
Views
83K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
10
Views
4K