Tension in a rope in an accelerating towplane (AP French 7-1)

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SUMMARY

The discussion centers on calculating the tensions in the tow ropes (A and B) of two identical gliders being towed by an accelerating plane. Initially, the tension in rope A is T(sub0) when the system is at constant velocity. Upon acceleration, the tensions are derived as T(ropeA) = T(sub0) + 2ma and T(ropeB) = 0.5 * T(sub0) + ma. The inclusion of T(sub0) accounts for the initial constant velocity and the forces acting on the gliders, including drag, which must be overcome during acceleration.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with tension forces in a system
  • Knowledge of drag force and its effects on moving bodies
  • Basic algebra for solving equations
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  • Study the effects of drag on moving objects in fluid dynamics
  • Learn about tension in multi-body systems in physics
  • Explore Newton's second law in the context of accelerating systems
  • Investigate the relationship between force, mass, and acceleration in practical scenarios
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Homework Statement


AP French Mechanics Problem 7-1

Two identical gliders, each of mass m, are being towed through the air in tandem. Initially they are traveling at a constant speed and the tension in the tow rope A is T(sub0). The tow plane then begins to accelerate with an acceleration A. What are the tensions in A and B immediately after this acceleration begins?

Crude Drawing

Glider2 (Mass m) ---- rope B ----- Glider1 (Mass m) ----- rope A ------ Tow Plane (Initially at Rest then accelerating)

Homework Equations

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The Attempt at a Solution

[/B]

This is what I tried:

Initially at constant velocity:

Forces on Glider1: T(rope A) - T(rope B) = 0

Since T(ropeA) == T(sub0),
then T(ropeB) == T(sub0)

When Tow Plane Starts to Accelerate:

1) I assumed that entire system accelerated the same

Forces on Glider1:
T(ropeA) - T(ropeB) = m * a (1) (where m is mass of Glider 1)

Forces on Glider2:
T(ropeB) = m* a (2) (where m is mass of Glider2)

Therefore,

substituting, equation (2) into equation (1),

T(ropeA) = 2*m*a.

However, in the back of the book the answer states:

T(ropeA) = T(sub0) + 2ma
T(ropeB) = .5 * T(sub0) + ma

I just want to know why the initial condition of T(sub0) is included, though I assume it is because of the constant velocity at the beginning and the plane accelerating in relation to that initial velocity, Also, if it would helpful if someone could point out flaws in my logic.

Thanks.
 
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If the plane and gliders are initially traveling at constant speed, with tensions in the ropes pulling the gliders forward, there must be an equal force pushing them back. Where does that force come from and what is it called? Does that retarding force disappear when the plane starts to accelerate?

What does the force in the ropes have to be in order to (1) overcome the retarding force and (2) provide the acceleration.
 
andrewkirk said:
If the plane and gliders are initially traveling at constant speed, with tensions in the ropes pulling the gliders forward, there must be an equal force pushing them back. Where does that force come from and what is it called? Does that retarding force disappear when the plane starts to accelerate?

What does the force in the ropes have to be in order to (1) overcome the retarding force and (2) provide the acceleration.

I would think the force would come from Drag and that it would equivalent to T(sub0) since the forces must balance out. When the plane accelerates this force does not disappear.

Therefore initial situation (constant v):

Forces on Glider 1:

T(ropeA) - (TropeB) - Force(drag) = 0 (1)

Forces on Glider 2:

T(ropeB) - Force(drag) = 0 (2), therefore Force(drag) = T(ropeB)

Substituting (2) into (1) and substituting T(sub0) for T(ropeA):

T(sub0) = 2 F(drag)

F(drag) = .5 * T(sub0)

Accelerating situation:

Glider 2)

T(ropeB) - F(drag) = ma - > T(ropeB) = ma + .5 *T

Glider 1)

T(ropeA) - T(ropeB) - F(drag) = ma

-> T(ropeA) = T(sub0) + 2ma

Thanks for the help.

From now on, ill work applicable constant velocity problems in the same way.
 

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