B Problems regarding electrostatic forces in everyday levitation

AI Thread Summary
The discussion addresses confusion regarding electrostatic forces and levitation in physics. It clarifies that oxygen is not the most abundant element in shoe atoms but may be present in an oxide layer. The force per atom is explained by the distribution of electrons, with four electrons facing outward at any moment. The relationship between electric force and weight is highlighted, indicating that electrostatic repulsion balances the gravitational force acting on a person. Understanding these concepts is essential for grasping the principles of everyday levitation.
jackiepollock
Messages
11
Reaction score
2
Hello! I'm reading this part of the A-level physics book and finding a few places that I couldn't wrap my head around. They are underlined.

1) When saying oxygen, is it saying that oxygen is the most abundant element in the shoe atoms?

2)I am not too sure why the force per atom is shared between four electrons when there are eight in each oxygen atom. Despite the explanation it has given, I don't finding making sense and couldn't picture it.

3)When I follow the calculations, I see that the electric force is basically derived from the weight of the man, is it because the weight has caused a normal force, which is assumed to be the electric force?

Thank you for the help!
Screenshot 2021-08-03 at 19.54.05.png
Screenshot 2021-08-03 at 19.54.10.png
 
Physics news on Phys.org
1. Both floor and shoe, I think. Even if this isn't true of the bulk materials, there is probably an oxide layer on the surface.
2. On average, at any given moment, four electrons will be on one side of the atom and four on the other. So there will be 4 "facing out" from the surface.
3. The electrostatic repulsion of the electrons (pushing the man up) balances the weight of the man (pulling him down).
 
Thread 'Inducing EMF Through a Coil: Understanding Flux'
Thank you for reading my post. I can understand why a change in magnetic flux through a conducting surface would induce an emf, but how does this work when inducing an emf through a coil? How does the flux through the empty space between the wires have an effect on the electrons in the wire itself? In the image below is a coil with a magnetic field going through the space between the wires but not necessarily through the wires themselves. Thank you.
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (Second part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8. I want to understand some issues more correctly. It's a little bit difficult to understand now. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. In the page 196, in the first paragraph, the author argues as follows ...
Back
Top