Product equality and sum of squares equality puzzle

[K Sengupta]

Substitute each of the capital letters by a different digit from 0 to 9 to satisfy this set of cryptarithmetic relationships. None of the numbers can contain any leading zero.

ABCD*EF=GHJB*KE, and:

(EH)² + (KC)² = (KH)²

 

[I like Serena]

Spoiler

abcd*ef=ghjb*ke
9807*14=6538*21

(eh)² + (kc)² = (kh)²
(15)² + (20)² = (25)²