Product of Groups: Understand Max Subgroups & Taking the Product of Groups

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SUMMARY

The discussion focuses on understanding the product of groups, specifically the direct product of groups such as S7 x Z7 and Z2 x Z3. A maximal normal subgroup is defined as a normal subgroup that is not properly contained in another proper normal subgroup. The direct product of two groups A and B is represented as A x B, which consists of all ordered pairs (a, b) where a is in A and b is in B. Additionally, it is established that if n and m are coprime, then the direct product Zn x Zm is isomorphic to Znm, exemplified by Z2 x Z3 being isomorphic to Z6.

PREREQUISITES
  • Understanding of group theory concepts, including groups and subgroups
  • Familiarity with normal subgroups and their properties
  • Knowledge of direct products in group theory
  • Basic understanding of isomorphism in algebra
NEXT STEPS
  • Study the properties of maximal normal subgroups in group theory
  • Learn about the structure and properties of symmetric groups, specifically S7
  • Explore the concept of isomorphism in more depth, particularly in relation to direct products
  • Investigate the implications of coprimality in direct products of cyclic groups
USEFUL FOR

Mathematicians, students of abstract algebra, and anyone interested in deepening their understanding of group theory and its applications.

DanielThrice
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I'm having trouble understanding the product of groups and their max normal subgroups. What does it mean to be a max subgroup? How do I take the product of two groups?
How do I do it for something like S7 X Z7 ?
 
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It's just the cartesian product (like you can make out of any collection of sets), and the group operation on the product is done componentwise, using the operation from each factor group. Surely this definition is in your textbook.

A maximal (normal) subgroup is a (normal) subgroup not properly contained in another proper (normal) subgroup. Note in particular this does not imply that a maximal normal subgroup contains every other normal subgroup.
 
This is my first post on this forum, so I hope I don't break any rules and give you too much help for your homework :p

But I remember being very confused when I first bumped into the direct product of groups.

If we start with the basic definition: If A and B are both groups then A x B = {(a,b) | a [tex]\in[/tex] A, b[tex]\in[/tex] B}, so it is the set of all (a,b) where a is in A and b is in B.

then for example to find Z2 x Z3:

we know {0,1} is Z2 and {0,1,2} is Z3
so Z2 x Z3 is the set of all (a,b) where a is in {0,1} and b is in {0,1,2}
therefore Z2 x Z3 = {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2)}

obviously this is very clumsy and long, so if you're working with direct products it's useful to note that when Zn x Zm, if n and m are coprime then Zn x Zm is isomorphic to Znm.

So in the example above, Z2 x Z3 is isomorphic to Z6.
 

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