Projectile Distance: Earth vs. Moon

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SUMMARY

The horizontal distance traveled by a projectile on Earth differs from that on the Moon due to variations in gravitational acceleration. The calculations provided demonstrate that the initial velocity for a projectile on Earth is 0.19 m/s, while on the Moon it is 0.745 m/s, indicating a significant difference in projectile motion. The formulas used are Vxoearth=x√(g/2y) for Earth and Vxomoon=x√((1/6)g/2y) for the Moon, where g is the acceleration due to gravity. Understanding these calculations is essential for accurately comparing projectile distances in different gravitational environments.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with gravitational acceleration values (9.8 m/s² for Earth, 1.63 m/s² for Moon)
  • Ability to apply kinematic equations in physics
  • Basic knowledge of unit conversions (e.g., cm to m)
NEXT STEPS
  • Study the effects of gravity on projectile motion in different celestial bodies
  • Learn about kinematic equations and their applications in physics
  • Explore advanced projectile motion simulations using software tools like PhET
  • Investigate real-world applications of projectile motion in aerospace engineering
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in the effects of gravity on motion in different environments.

jdawg
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Homework Statement



Would the horizontal distance traveled by a projectile on Earth be the same as one on the moon? I feel like the distances would be different, but when I was calculating the initial velocity of the projectile on the moon I used the same x value(distance) that I did for earth. Wouldn't gravity have an affect on the distance traveled?

Homework Equations



Vxoearth=x√(g/2y)
Vxomoon=x√((1/6)g/2y)

The Attempt at a Solution

 
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It would. Gravity affects the maximum height that an object can go, hence it affects time as well, and time affects the horizontal displacement. Can you please show your calculations?
 
Height: y=14.1cm=0.141 m
Distance: x=31.3 cm= 0.313 m

Vxoearth=(0.313)*√(9.8/2*0.141)=0.19 m/s

Vxomoon=(0.313)*√(1/6*9.8/2*0.141)= 0.745 m/s

But what's confusing me is the way they worded the question. They told me to use my x measurement and y height from the experiment when calculating the initial velocity for the moon. Then they ask if the x values measured on the moon would be the same as the x values measured on earth. Why would they tell me to use the same x value if they would be different?
 
As always, please follow the HW template when posting to these forums. We can't judge the wording of the problem if you don't provide it verbatim.
 
Sorry, I'm still kind of new to this forum. But I think I figured out what the question meant. Thanks for the help!
 

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