A projectile is fired at an upward angle of 45 degrees from the top of a 165m Cliff with a speed of 175 m/s. what will be its speed when it strikes the ground below? (Use conservation of energy and neglect air resistance.)
E= Ke +Pe
1/2 mv^2 + mgh = 1/2mv^2 +mgh
v^2= Vo^2 +2a(xo-x)
The Attempt at a Solution
I honestly don't know where to start, or if I have the right equations? A point in the right direction would be appreciated.