a baseball player hits a home run. The ball's velocity as it leaves the bat is 45m/s at an angle of 36.9° above the horizontal. At the point of impact with the bat, the ball is 1 m above ground level, and as it clears the fence it is back down to 11 m above ground level. How far from home plate is the fence at this point?
linear motion equations
basic sin and cos
The Attempt at a Solution
so I started with finding the Vv and the Vh velocties
vh= 45cos6.9= 36.0
Vv= 45sin36.9 = 27.0
then I organized the information I had into two seperate headings
v1: 27 m/s
*I found the time using the quadratic formula and came up with 5.5 seconds
* I calculated the total distance the ball travelled using the formula d = v×t and got 198 m
* calulated the v2 for the Vv to be 27.4 m/s using linear motion equation
I'm thinking i need a colum for the fence distance now, however, this part is slightly iffy.
Vh for fence
Vv for fence
At this point I've hit a dead end.