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## Homework Statement

a baseball player hits a home run. The ball's velocity as it leaves the bat is 45m/s at an angle of 36.9° above the horizontal. At the point of impact with the bat, the ball is 1 m above ground level, and as it clears the fence it is back down to 11 m above ground level. How far from home plate is the fence at this point?

## Homework Equations

quadratic formula

linear motion equations

basic sin and cos

v=d/t

## The Attempt at a Solution

so I started with finding the Vv and the Vh velocties

vh= 45cos6.9= 36.0

Vv= 45sin36.9 = 27.0

then I organized the information I had into two seperate headings

Vv

v1: 27 m/s

v2:*27.4m/s

a: -9.8m/s

t:*5.5

d: -1m

and Vh

vave: 36m/s

t:*5.5

d:*198m

*I found the time using the quadratic formula and came up with 5.5 seconds

* I calculated the total distance the ball travelled using the formula d = v×t and got 198 m

* calulated the v2 for the Vv to be 27.4 m/s using linear motion equation

I'm thinking i need a colum for the fence distance now, however, this part is slightly iffy.

Vh for fence

vave:

t:T

d: 198-D

Vv for fence

v1:

v2:

a:-9.8m/s

t:T

d: -11m

At this point I've hit a dead end.