1. The problem statement, all variables and given/known data a baseball player hits a home run. The ball's velocity as it leaves the bat is 45m/s at an angle of 36.9° above the horizontal. At the point of impact with the bat, the ball is 1 m above ground level, and as it clears the fence it is back down to 11 m above ground level. How far from home plate is the fence at this point? 2. Relevant equations quadratic formula linear motion equations basic sin and cos v=d/t 3. The attempt at a solution so I started with finding the Vv and the Vh velocties vh= 45cos6.9= 36.0 Vv= 45sin36.9 = 27.0 then I organized the information I had into two seperate headings Vv v1: 27 m/s v2:*27.4m/s a: -9.8m/s t:*5.5 d: -1m and Vh vave: 36m/s t:*5.5 d:*198m *I found the time using the quadratic formula and came up with 5.5 seconds * I calculated the total distance the ball travelled using the formula d = v×t and got 198 m * calulated the v2 for the Vv to be 27.4 m/s using linear motion equation I'm thinking i need a colum for the fence distance now, however, this part is slightly iffy. Vh for fence vave: t:T d: 198-D Vv for fence v1: v2: a:-9.8m/s t:T d: -11m At this point I've hit a dead end.