Projectile Motion airplane final speed

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SUMMARY

The discussion focuses on calculating the final speed of supplies dropped from an airplane flying at 914 m above the ocean at a horizontal speed of 116 km/hr (32.222 m/s). The vertical component of velocity was calculated using the equation Vfy² = Voy² + 2ay, resulting in an incorrect value of -133.845 m/s. Participants emphasized the need to combine both the vertical and horizontal components to determine the overall final speed upon landing.

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black_hole
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Homework Statement



An airplane flying 914 m above the ocean at 116 km/hr is supposed to drop a box of emergency supplies to the survivors of a shipwreck on an island. At what final speed will the supplies land on the island?


Homework Equations





The Attempt at a Solution



So Vx = 32.222 m/s, is Voy = 0 m/s?
a = -9.8 m/s/s and y = -914 m?

So I did Vfy^2 = Voy^2 +2ay and got -133.845 m/s, but that is not right...
 
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black_hole said:
So I did Vfy^2 = Voy^2 +2ay and got -133.845 m/s, but that is not right...
That's just the y-component of the velocity. Combine it with the x-component to figure out the speed.
 

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