- #1

- 11

- 0

**Would anyone willing to check my work on this vector question?**

I have an assignment due in a few days and was just wondering if someone could look over one of the questions from this assignment and see if I've done it correctly, as I still don't feel entirely confident with this yet.

So the question is: A baseball, thrown from the ground, lands on top of a building that is 15.5 m tall. If the ball is thrown at 22.0 m/s at an angle of 58.0° above the horizontal, find each of the following:

a) horizontal and vertical components of initial velocity

Vo= 22.0 m/s, so Voy=22sin(58)=18.7 m/s, and Vox=22cos(58)=11.7 m/s

b) final vertical velocity

Vfy^2=Voy^2+2AyΔXy

= 18.7^2 + 2(-9.8)(15)

= +/- sqrt(55.69)

Vfy = -7.46 m/s

c) time of flight

a=v/t therefore t=v/a

t= -7.46-18.7/-9.8

t= 2.67s

d) horizontal displacement

ΔXx=Vox*t+(1/2*Ax*t^2)

=11.7*2.67+0

ΔXx=31.2m

e) final vector velocity (HINT: Use both vertical and horizontal components)

Vf^2 = Vfy^2+Vfx^2

Vf=-13.88 m/s

f) maximum height reached above the ground

Set Vfy=0

-Voy^2/2Ay=ΔXy

-(18.7^2)/(2*-9.8)=ΔXy

17.8m=ΔXy

Last edited: