Could someone check my work on this vector assignment question?

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The discussion revolves around a vector assignment question involving projectile motion. The user calculates the horizontal and vertical components of the initial velocity of a baseball thrown at 22.0 m/s at an angle of 58.0°, yielding values of 18.7 m/s and 11.7 m/s, respectively. The final vertical velocity is determined to be -7.46 m/s, with a time of flight of 2.67 seconds and a horizontal displacement of 31.2 meters. The maximum height reached above the ground is calculated to be 17.8 meters, demonstrating a comprehensive understanding of the physics involved.

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Would anyone willing to check my work on this vector question?

I have an assignment due in a few days and was just wondering if someone could look over one of the questions from this assignment and see if I've done it correctly, as I still don't feel entirely confident with this yet.

So the question is: A baseball, thrown from the ground, lands on top of a building that is 15.5 m tall. If the ball is thrown at 22.0 m/s at an angle of 58.0° above the horizontal, find each of the following:

a) horizontal and vertical components of initial velocity

Vo= 22.0 m/s, so Voy=22sin(58)=18.7 m/s, and Vox=22cos(58)=11.7 m/s

b) final vertical velocity

Vfy^2=Voy^2+2AyΔXy
= 18.7^2 + 2(-9.8)(15)
= +/- sqrt(55.69)
Vfy = -7.46 m/s

c) time of flight

a=v/t therefore t=v/a
t= -7.46-18.7/-9.8
t= 2.67s

d) horizontal displacement

ΔXx=Vox*t+(1/2*Ax*t^2)
=11.7*2.67+0
ΔXx=31.2m

e) final vector velocity (HINT: Use both vertical and horizontal components)

Vf^2 = Vfy^2+Vfx^2
Vf=-13.88 m/s

f) maximum height reached above the ground
Set Vfy=0
-Voy^2/2Ay=ΔXy
-(18.7^2)/(2*-9.8)=ΔXy
17.8m=ΔXy
 
Last edited:
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