Projectile Motion and Gravity: Calculating Height of a Projectile

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Homework Help Overview

The problem involves a projectile shot straight up from the Earth's surface at a high speed, raising questions about its maximum height and the applicability of projectile motion principles versus gravitational effects. The context is related to both projectile motion and gravitational theory.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss whether the problem is purely a projectile motion issue or if it requires consideration of varying gravitational effects due to the high initial speed. Some mention the conservation of energy as a relevant concept.

Discussion Status

The discussion is exploring multiple interpretations of the problem, with some participants suggesting different approaches, such as using gravitational potential energy and conservation of energy principles. There is no explicit consensus on the best method to apply.

Contextual Notes

Participants note the high initial speed of the projectile, which raises concerns about the assumption of constant gravitational acceleration. The discussion reflects uncertainty regarding the appropriate equations to use in this scenario.

tibessiba
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Is this projectile motion??

Homework Statement



A projectile is shot straight up from the Earth's surface at a speed of 1.30×104 km/hr.

How high does it go?



Is this just a projectile motion problem? Or is it different because it has something to do with the theory of gravity? (because that is the section we are on in class).
 
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Just a projectile motion problem.
 
Oh, ok...

Thanks
 
I think you mean 1.30*10^4km/hr, but I could be wrong. If so then it is fast enough that you can't take g=constant. So it's a gravity problem. It might be handy to know something about conservation of energy.
 
Oops.. Yes I do mean 1.30*10^4...
 
Ok, then you just need to know an expression for gravitational potential energy that is more general than mgh.
 
I think it's a free-fall motion problem. You use the UAM (uniformly accelerated motion) formula d = (Vf^2 - Vi^2) / 2g, but make sure that g is negative since the projectile was shot upwards.
 
Rylynn97 said:
I think it's a free-fall motion problem. You use the UAM (uniformly accelerated motion) formula d = (Vf^2 - Vi^2) / 2g, but make sure that g is negative since the projectile was shot upwards.

Wrong, the projectile is moving at nearly orbital velocity. You can't take 'g' constant.
 
Use conservation of energy principle.
KE = 1/2.mv^2
PE= GMm/(R + h). Substitute GM = gR^2. Find the value of h
 

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