1. The problem statement, all variables and given/known data From a height of 23 m, a ball is thrown horizontally. If it hits the ground with a speed that is three times its initial speed, what is the initial speed? vertical: a = -9.8, x = -23, t = ?, V0=?, V = 3V0 horizontal: ? x is displacement 2. Relevant equations Possibly relevant: V = Vo + at x-x0 = Vot + .5at2 x-x0 = Vt - .5at2 x-x0 = .5(V0+ v)t V2 = V02 + 2a(x-x0) 3. The attempt at a solution Seems simple, but I have tried and cannot do this problem. Seems like there is not enough info. Solving the system of the following equations for vertical motion x-x0 = Vot + .5at2 x-x0 = Vt - .5at2 found that t = 2.1447, but I am not sure if this is correct. After that I just didn't know what to do. For horizontal movement, it seems like there is only time and the fact that the final velocity is 3 times the initial velocity.