Projectile Motion Ball Hurl Question

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To determine the widest river that can be crossed by throwing a ball at an initial speed of 30 m/s, the range equation d = (v_i^2 sin 2θ) / g is used. The maximum range occurs when the angle θ is 45 degrees, as this maximizes the value of sin 2θ. Substituting the initial speed and gravitational acceleration into the equation allows for the calculation of the maximum distance. The discussion emphasizes the importance of using the correct angle for optimal projectile motion. Ultimately, the correct approach leads to finding the solution to the problem.
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Homework Statement



If you can hurl a ball so that its initial speed is 30m/s, what is the widest river you can throw it across?

Homework Equations


The range equations,
t=2(vi)(sintheta)/g

d=visin2theta/g


The Attempt at a Solution



I know you have to use components so what I got what Vx=30sintheta and Vy=30costheta

I don't know what to do next or how to sub it in because there isn't a angle given . Can someone please help me. Thanks
 
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You have your formula for the range as

d = \frac{v_i sin2 \theta}{g}

For you to throw it at the max range, you'd need to throw it such that your angle θ and hence sin2θ is maximum.

What is the maximum value that sin2θ can be?
 
rock.freak667 said:
You have your formula for the range as

d = \frac{{v_{0}}^2 sin2 \theta}{g}

For you to throw it at the max range, you'd need to throw it such that your angle θ and hence sin2θ is maximum.

What is the maximum value that sin2θ can be?

Forgot a square!
 
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The angle must be 45 degrees to get max range right?
 
Oh ok, I got the answer. Thanks so much !
 
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