Projectile Motion Ball Hurl Question

Click For Summary

Homework Help Overview

The problem involves projectile motion, specifically determining the maximum distance a ball can be thrown across a river given an initial speed of 30 m/s. The discussion centers around the application of range equations in projectile motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of range equations and the need to consider the angle of projection. Questions are raised about how to proceed without a given angle, and the maximum value of the sine function is explored.

Discussion Status

Some participants have provided guidance on maximizing the range by suggesting the angle of projection that yields the maximum sine value. There is an acknowledgment of the need for clarification on the angle to achieve maximum range.

Contextual Notes

There is a lack of explicit information regarding the angle of projection, which is crucial for solving the problem. Participants are navigating through assumptions about optimal angles in projectile motion.

yoyo16
Messages
35
Reaction score
0

Homework Statement



If you can hurl a ball so that its initial speed is 30m/s, what is the widest river you can throw it across?

Homework Equations


The range equations,
t=2(vi)(sintheta)/g

d=visin2theta/g


The Attempt at a Solution



I know you have to use components so what I got what Vx=30sintheta and Vy=30costheta

I don't know what to do next or how to sub it in because there isn't a angle given . Can someone please help me. Thanks
 
Physics news on Phys.org
You have your formula for the range as

d = \frac{v_i sin2 \theta}{g}

For you to throw it at the max range, you'd need to throw it such that your angle θ and hence sin2θ is maximum.

What is the maximum value that sin2θ can be?
 
rock.freak667 said:
You have your formula for the range as

d = \frac{{v_{0}}^2 sin2 \theta}{g}

For you to throw it at the max range, you'd need to throw it such that your angle θ and hence sin2θ is maximum.

What is the maximum value that sin2θ can be?

Forgot a square!
 
  • Like
Likes   Reactions: 1 person
The angle must be 45 degrees to get max range right?
 
Oh ok, I got the answer. Thanks so much !
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
795
Replies
5
Views
2K
Replies
12
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K