Projectile Motion ball throw help

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Homework Help Overview

The problem involves a ball thrown from a 15m cliff at a 30-degree angle, with a total flight time of 10.4 seconds. Participants are tasked with determining the initial velocity, maximum height, and final velocity of the ball, engaging in discussions around projectile motion concepts.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to start the problem, considering dividing the motion into sections and questioning the validity of using certain equations given the vertical component of the velocity. Other participants suggest working in sections, using kinematic equations, and drawing diagrams to clarify the motion.

Discussion Status

Participants are exploring various approaches to the problem, with some suggesting breaking the motion into stages and using simultaneous equations to solve for the initial speed. There is a recognition of the need to consider both vertical and horizontal components of motion, but no consensus has been reached on a specific method.

Contextual Notes

Participants note the challenge of working without an initial velocity provided, which adds complexity to the problem. The discussion reflects a mix of assumptions and interpretations regarding the equations applicable to projectile motion.

d21
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Homework Statement


A ball is thrown off of a 15m cliff at an angle of 30 degrees above the horizontal and strike the ground 10.4 seconds later. Determine the initial velocity of the ball, the maximum height of the ball, and impact (final) velocity of the ball.

Homework Equations


vo=vf+at
y=.5at+volt
x=volt

The Attempt at a Solution


I'm really out of my depth on this problem. I really just have no clue where to begin, since I'm used to being given the initial velocity of the ball. I had an idea to try to divide up the time of the problem into two sectors, where the ball is in its parabolic motion in one section and the other where it comes back to the same level that it was launched at and continues to the ground. the time would be √2h/g correct? But can I use this even though there's a y component to the velocity? Is any of this even correct? How do I do this problem?

Or can I just say y=.5gt^2+volt
-15=.5(-10)(10.4)^2+vo(10.4)?
Vo=53.44?

Also isn't this just the vertical component of Vo? So shouldn't the full Vo be
Voy=VoSin30
53.44=VoSin30
Vo=106.88?
 
Last edited:
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well, you do have to work in sections. when the ball comes back to the same level on the other side, it has the same magnitude of vertical velocity (the direction is opposite) it had at launch time. from here on, you know the height to the bottom, calculate final vertical velocity.
Use the equation
V^2 - Vo^2 =2as

it should become simple from here on.
 
NahilSh said:
you do have to work in sections.
That would be if you were using the standard ballistics equations.
Alternately - draw a v-t diagram for horizontal and vertical components of the motion.
Or just applying the kinematic equations, as d21 has done.

d21 said:
I'm used to being given the initial velocity of the ball.
Welcome to PF;
Proceed as you normally would, just leave the initial velocity as a variable.
You'll end up with a system of simultaneous equations which you can solve for the initial speed.

As NahilSH said, you can finess the process by realising that the speed is the same at the initial height but coming down.
 
Simon Bridge said:
That would be if you were using the standard ballistics equations.
Alternately - draw a v-t diagram for horizontal and vertical components of the motion.
Or just applying the kinematic equations, as d21 has done.

yeah, true...:redface: but it does help to work in sections to simplify the process.
 
It can help to break the process into stages, and solve each stage in turn. Yep.
 

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