a ball is thrown horizontally from a height of 16.01m and hits the groung with a speed that is 5.0 times its initial speed. what was the initial speed?
The Attempt at a Solution
dy= -16.01m (because the ball is falling that distance)
a= -9.8 m/s^2
vf^2= vi^2 + 2ad
(5vi)^2= vi^2+ 2(-9.8)(-16.01)
25 (vi^2)= vi^2+ 313.8
what should i do next if this is right?