Projectile Motion: Calculating Distance and Velocity with Two Formulas

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Homework Help Overview

The problem involves projectile motion, specifically calculating the distance a stone travels when thrown at an angle and hitting a wall at a certain height. The scenario includes two potential outcomes based on the stone's trajectory.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss which formulas are appropriate for calculating the stone's range and vertical motion. There is uncertainty about the implications of the two possible answers related to the stone's trajectory.

Discussion Status

Some participants have provided guidance on the formulas to use for vertical and horizontal motion. There is ongoing exploration of the meaning behind the two different scenarios of the stone hitting the wall.

Contextual Notes

Participants are considering the implications of the stone's height at impact and the conditions under which it could be rising or falling. There is mention of formatting issues with mathematical expressions.

jason.frost
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1. A boy standing on the ground throws a stone with velocity 20 m/s at an angle of 30 degrees above the horizontal. It hits the wall of a nearby building at a position 3.0m above the level at which it was thrown. How far is the from the boy? (Two answers are possible. Give both. One represents the stone on its way up, the other on the way down.)



2. I guess I mainly need some help with which formula to use.



3. I am thinking that you will use Range=(Vo^2*sin2theta)/(|g|) and V^2x = V^2ox + 2axX. Sorry if those look bad. Is there any sub or sup script formatting? Am I thinking right with the formulas? I really don't even know what the second one finds for you.
 
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You would use

[tex]y(t) = y_o + v_{yo} t - \frac {1}{2} g t^2[/tex]

for vertical motion and

[tex]x(t) = x_0 + v_{xo} t[/tex]
for horizontal motion. (Btw, see this thread for LaTex formatting.)
 
Thanks.

What does the question mean by one answer is for "the way up and the other for the way down"?
 
The stone could still be rising when it hits the wall ("on the way up") or it might have reached its maximum height prior to hitting the wall ("on the way down"). The two scenarios yield two different answers.
 

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