Projectile Motion: Determine v_0 to go over a fence

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Homework Help Overview

The problem involves calculating the initial speed \( v_0 \) required for a baseball to clear a fence of height \( H \) at a distance \( D \), given a launch angle \( \theta \). The discussion centers around the application of projectile motion equations to derive this speed.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use the equations of motion to express \( v_0 \) in terms of \( D \) and \( H \), but encounters a complex equation. Some participants question the clarity and correctness of the equations used, while others suggest plotting the equations to verify the results.

Discussion Status

The discussion is ongoing, with some participants providing suggestions for simplification and verification of the approach taken. There is no explicit consensus on the correctness of the original poster's method, but guidance has been offered regarding potential next steps.

Contextual Notes

Participants note potential assumptions about the initial height of the projectile and the need for a single equation relating horizontal and vertical motions without time as a variable. There is also mention of a possible typo in the equations provided by the original poster.

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Homework Statement


You're the new home run hitter for a baseball team. Your job is to hit the ball over a fence D away and H high. For a given angle θ calculate the speed with which the ball must be hit v0 to go over the top of the fence.

Homework Equations


1. y = y0+(v0*sinθ)-½gt2
2. x = v0*t*cosθ

The Attempt at a Solution



I tried using H as my y value from eq. 1 and D as my x value in eq. 2. I solved for v0 in eq. 2 (D/(t*cosθ)), then attempted to eliminate t by solving for it in equation 1 using the quadratic formula. Then I substituted the result into the D/(t*cosθ) equation.

The result is a very bulky equation that I'm unsure is correct. A tutor said my reasoning was sound, and was unable to come up with a more simplified answer himself. What do you guys think? Am I even on the right track here?
 
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Dr. Courtney said:
it's complicated.

The problem, the answer, or both?
 
The best double check is to plot the resulting parametric equations with real numbers and see if it clears the fence.
 
Your quoted equation for y is missing something. I assume that's just a typo.
I assume H is the height relative to the point of impact, so y0=0.
The only use of t here is to connect the horizontal and vertical motions, so I would start by obtaining a single equation relating x and y, with t absent.
After that it does not look complicated to me. You can get a small simplification by using the formulae for sin(2θ) and cos(2θ).
Please post your working.
 

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