If an object is being launched from the top of a staircase 1.31m high from a pipe 16cm long, at an angle of 60 degrees. Find where the object will land if the initial velocity is 5.442m/s.
dx = 2v1^2sinθcosθ / g
dy = vyΔt+1/2gΔt^2
dx = vxΔt
The Attempt at a Solution
I found the components to be
vx = 2.721
vy = 4.713
then i just used these in the two methods
the answers should both be the same, but the dx i got from both was very different
Am i doing something wrong? which one would be the correct answer?
Also, for the first method, i put 120 degrees as negative as it is below my reference point, or it would give me a neg. distance.