1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Projectile motion on inclined plane

  1. Oct 19, 2016 #1
    1. The problem statement, all variables and given/known data
    As shown in the figure below, small object A is projected upward along a smooth slope forming angle α with the horizontal plane, with initial speed v0 in the direction of angle θ from the horizontal within the slope’s plane. The object continues to travel along the surface of the slope. Let us denote as h the maximum height that A attains on the slope, where height is measured vertically from A’s starting point. Find v0
    aszx_zpsz5raqsdb.png

    2. Relevant equations
    projectile motion

    3. The attempt at a solution
    I interpret the question as projectile motion with total angle (α + θ) with respect to horizontal plane.

    At maximum height, vertical speed is zero, so:
    vy2 = voy2 - 2gh

    v0 = √(2gh) / (sin (α + θ))

    But the answer is v0 = √(2gh) / (sin θ)

    Do I interpret the question wrongly? Or there is mistake in my working?
     
    Last edited: Oct 19, 2016
  2. jcsd
  3. Oct 19, 2016 #2

    CWatters

    User Avatar
    Science Advisor
    Homework Helper

    The angles don't add in the way you think.
     
  4. Oct 19, 2016 #3
    You misinterpreted the question. The ball moves "within" the slopes plane, I mean, it does not go "above" the plane.
     
  5. Oct 19, 2016 #4
    I get the hint. Thanks a lot
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Projectile motion on inclined plane
Loading...