Projectile motion - finding initial velocity with no time

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Homework Help Overview

The problem involves projectile motion, specifically calculating the initial velocity required for a basketball to reach a hoop from a given distance and height, without knowing the time of flight. The scenario includes a basketball player shooting from a height of 1.94 m towards a basket at 3.05 m, positioned 10.0 m away, at an angle of 42.0°.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss breaking the problem into x and y components, considering the effects of gravity on the vertical motion and the constant velocity in the horizontal direction. There are questions about how to relate the time of flight to both components and how to utilize the equations of motion effectively.

Discussion Status

Some participants have suggested a method to find the time from the horizontal motion equation and then use that time in the vertical motion equation to solve for the initial velocity. There is acknowledgment of the relationship between time in both components, but no consensus on a complete solution has been reached.

Contextual Notes

The discussion highlights the challenge of solving for initial velocity without a known time, and participants are navigating through the equations of motion while considering the constraints of the problem setup.

KKuff
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Homework Statement



I'm having trouble finding the initial velocity without knowing the time.

A basketball player is standing on the floor 10.0 m from the basket. The height of the basket is H = 3.05 m, and he shoots the ball at an angle, θ = 42.0°, with the horizontal from a height of h = 1.94 m. At what speed must the player throw the basketball so that the ball goes through the hoop without striking the backboard?


Homework Equations



I'm not sure how to determine which equations I need, since there are at least 2 variables that I don't know in each one

V(f) = V(i) + at
X(f) = X(i) + (1/2)(V(i) + V(f))t
X(f) = X(i) + V(i)t + (1/2)at^2
V(f)^2 = V(i)^2 + 2a(X(f) - X(i))

The Attempt at a Solution



I know that I have to break up the problem into x and y components. So I would have the y-velocity component Vy = Vsin42.0 and the x-velocity component Vx = Vcos42.0. I know that for the y component I would have an acceleration of -9.8m/s and that for the x component that I would have no acceleration since it is a constant velocity, so that would make Vx(i) = Vx(f). The initial horizontal position is X(i) = 0 and the final horizontal position is X(f) = 10. The initial vertical position is Y(i) = 1.94 and the final vertical position is Y(f) = 3.05.

I just don't know how to put all of this information together in order to find the initial velocity. Any help will be appreciated.
 
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Welcome to PF!

Hi KKuff! Welcome to PF! :smile:

(try using the X2 and X2 icons just above the Reply box :wink:)

Call the speed v, then find t from the x equation, and use that value of t in the y equation, to solve for v …

what do you get? :smile:
 
I got about 10.6m/s. Thanks I appreciate it. Is t used since it would have the same value in both the x and the y components?
 
KKuff said:
Is t used since it would have the same value in both the x and the y components?

That's right! :smile:

(standard technique … sometimes it's t, sometimes it's x or y or even v :wink:)
 

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