- #1

Kaiser98

- 2

- 1

- Homework Statement
- A pitcher throws an overhand fastball from an approximate height of 2.65 m and at an

angle of 2.5° below horizontal. The catcher, catches the ball high in the strike zone, at a

height of 1.02 m above the ground. If pitcher's mound and home plate are 18.5 m apart,

what is the initial velocity of the pitch?

- Relevant Equations
- s = ut + 0.5 at^2

Answer given in book: 45.2 m/s

My reasoning was to use this kinematic equation to first get time of flight of the baseball using horizontal components, and then use this same equation again to find initial velocity.

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