1. The problem statement, all variables and given/known data A firefighter d=50 m away from a burning building directs a stream of water from a fire hose at an angle of θ=30° above the horizontal. The speed of the water stream is 40 m/s. a) What is the maximum height in the air that the water reaches? b) At what height h will the water strike the building? I found the Velocity for the horizontal component Vx = cos30*40=34.64m/s and the vertical component Vy= sin30*40 = 20m/s For part a, is the height 10.2m? I did [tex]\Delta[/tex]X=Vx*t 50m=34.64m/s*t t=1.44 seconds then plugged that in the equation [tex]\Delta[/tex]y=Vy*T+1/2at^2 which at max height is [tex]\Delta[/tex]y=1/2at^2 1/2(-9.8)(1.44)^2 = 10.2m Or would that be the height of the building?