Projectile Motion: Given Horizontal Distance Travelled and Time Taken

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SUMMARY

The discussion centers on the calculation of initial velocity (v0) for a projectile launched horizontally. Given a horizontal distance of 5 meters and a time of 2 seconds, the calculation of 5m divided by 2s yields an initial horizontal velocity (v0x) of 2.5 m/s. This value does not account for any vertical velocity component, as the projectile's motion is purely horizontal in this scenario. Therefore, the overall initial velocity (v0) cannot be determined solely from this calculation.

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zenythz
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Okay, so we did an experiment in physics class where we launched a projectile from Point A (on the floor). The projectile obviously traveled in a parabolic motion and ended at Point B (on the floor again, so no difference in launching and landing heights).

We measured the distance from Point A to Point B to be 5 meters. We timed the projectile to find that it took 2 seconds to travel from Point A to Point B.

Here's my question: does dividing 5m by 2s give us overall initial velocity (v0) or just the initial velocity of the horizontal component (v0x)?
 
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The 5m you measured was a horizontal distance, so 5m/2s can't possibly include any velocity in the y direction.
 

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