The question reads: Luke Skywalker is dropping a bomb down a ventilation shaft on the Death Star. The circular shaft has a diameter of 1m. When the bomb is released, Luke's X-wing start-fighter is 200m above the shaft's opening and 500m horizontally from the front edge of the opening. His ship is traveling at a velocity v0 at an angle θ
above the horizontal. If he wants the bomb to reach the front edge of the opening so that the bomb is moving toward a point on the other side of the shaft that is 10m below the opening, find the appropriate values of v0 and θ.
Velocity in the y direction: vy = 10vx
x= x0 + ((v0)(cosθ))t
y = y0 +((v0)(sinθ))t + .5at^2
time > 30sec
θ > 70°
100 < (v0) < 200 m/s
The Attempt at a Solution
So far I am stuck at: 200 = 4.9t^2 +10((v0)(cosθ))t. I am trying to get an equation to solve for t, but I seem to end up with two variables (v0 and θ) in one equation when I try. Please help this is due tomorrow (9-18) at 10 am!