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Projectile Motion given only x and y distance

  • Thread starter tbbtfan14
  • Start date
  • #1
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Homework Statement


The question reads: Luke Skywalker is dropping a bomb down a ventilation shaft on the Death Star. The circular shaft has a diameter of 1m. When the bomb is released, Luke's X-wing start-fighter is 200m above the shaft's opening and 500m horizontally from the front edge of the opening. His ship is traveling at a velocity v0 at an angle θ
above the horizontal. If he wants the bomb to reach the front edge of the opening so that the bomb is moving toward a point on the other side of the shaft that is 10m below the opening, find the appropriate values of v0 and θ.


Homework Equations


Velocity in the y direction: vy = 10vx
x= x0 + ((v0)(cosθ))t
y = y0 +((v0)(sinθ))t + .5at^2


Constraints:
time > 30sec
θ > 70°
100 < (v0) < 200 m/s


The Attempt at a Solution


So far I am stuck at: 200 = 4.9t^2 +10((v0)(cosθ))t. I am trying to get an equation to solve for t, but I seem to end up with two variables (v0 and θ) in one equation when I try. Please help this is due tomorrow (9-18) at 10 am!

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
1,065
10
Maybe we try reverse position.
The origin of frame of refrence at side of the shaft.

y=uyt -0.5at2
x=uxt => t=x/ux

y=uTanθ- 0.5a(x2/(u2Cos2θ)

2 unknowns and we have 2 points on the path equation.
 
Last edited:

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