Projectile Motion: Horizontal distance

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A jet flying at 250 m/s at a 20-degree angle releases a bomb from 200 m above the ground, prompting a discussion on calculating the horizontal distance traveled before impact. The initial horizontal and vertical velocities were calculated as approximately 234.923 m/s and 85.505 m/s, respectively. Participants suggested using the equations y = yi + viyt + (at^2)/2 and R (range) = vxt to solve for the range. It was emphasized that these equations derive from the constant acceleration formula, applicable under constant gravity conditions. Understanding the variables and their relationships is crucial for determining the bomb's horizontal travel distance.
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Homework Statement


A jet flying at 250m/s at an angle of 20 degrees above the horizontal releases a bomb 200m above the ground, how far does the bomb travel horizontally before hitting the ground?


Homework Equations


vix = vicosthetha
viy= visinthetha
not sure what else...

The Attempt at a Solution


vix= 234.923ms
viy= 85.505 ms

This is all I've managed to figure out so far, does anyone know more relevant equations that may help me out?
 
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okay so you have got the component velocities which is always a good start.

next step is to recognise the equations you will need.

try y=yi+viyt+(at2)/2

and R(range)=vxt

from these u must realize the variables you are given, what you want(range) and the variables you need to find


okay in reread your question and saw that you specifically asked for an equation.

you should know that the equations i gave above can be derived from the equation for constant acceleration( in this case constant gravity).

this equation is x=xi+vit+at2/2

where x is th final DISPLACEMENT, xi is initial displacement tis time and a is the CONSTANT acceleration. this formula does not work with variable acceleration
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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