Projectile Motion (in a vaccum)

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SUMMARY

The discussion focuses on the calculations involved in projectile motion in a vacuum, specifically addressing the relationship between time of flight and maximum height. The key equation presented is v0² = 16D/(cos(α)²tan(α)), highlighting the importance of the cosine and tangent functions in determining projectile parameters. The final height is confirmed to be zero at impact, and the time to reach maximum height is established as half of the total time of flight. The resolution of the issue was facilitated by user Dick, who provided critical insights into the calculations.

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  • Understanding of basic physics concepts related to projectile motion
  • Familiarity with trigonometric functions, specifically cosine and tangent
  • Knowledge of kinematic equations in a vacuum environment
  • Ability to interpret graphical representations of motion
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  • Study the derivation of projectile motion equations in a vacuum
  • Learn how to apply trigonometric identities in physics problems
  • Explore the effects of initial velocity on projectile trajectories
  • Investigate the impact of angle of launch on maximum height and range
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Students of physics, educators teaching projectile motion concepts, and anyone interested in the mathematical modeling of motion in a vacuum.

RogerDodgr
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issue resolved; thanks dick

Given are listed in photo:
t_f=time final (at impact)
y_max = max height
v_o = initial velocity
final height = initial height = 0
x_f =D = final distance

I am having a problem with this because I know max height time must be half of final time at impact (zero height):
http://www.sudokupuzzles.net/blstc.gif
 
Last edited by a moderator:
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You lost a cos(alpha) around the middle of the page. v0^2=16*D/(cos(alpha)^2*tan(alpha)). Note the squared on the cos(alpha).
 

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