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Projectile Motion (in a vaccum)

  1. Mar 15, 2008 #1
    issue resolved; thanks dick

    Given are listed in photo:
    t_f=time final (at impact)
    y_max = max height
    v_o = initial velocity
    final height = initial height = 0
    x_f =D = final distance

    I am having a problem with this because I know max height time must be half of final time at impact (zero height):
    [​IMG]
     
    Last edited: Mar 15, 2008
  2. jcsd
  3. Mar 15, 2008 #2

    Dick

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    You lost a cos(alpha) around the middle of the page. v0^2=16*D/(cos(alpha)^2*tan(alpha)). Note the squared on the cos(alpha).
     
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