Projectile motion -- launched 60° above the horizontal

[thegoosegirl42]

Homework Statement

A projectile is launched at an initial speed of 30 m/s at an angle of 60° above the horizontal. Calculate the magnitude and direction of its velocity (a) 2s and (b) 5s after launch

Homework Equations

x=v*t in the x dimension
x= x+vt+(1/2)at^2

The Attempt at a Solution

I tried going through with the x dimension to solve for acceleration but the acceleration in the y is 9.8.

 

[SteamKing]

Homework Statement

A projectile is launched at an initial speed of 30 m/s at an angle of 60° above the horizontal. Calculate the magnitude and direction of its velocity (a) 2s and (b) 5s after launch

Homework Equations

x=v*t in the x dimension
x= x+vt+(1/2)at^2

The Attempt at a Solution

I tried going through with the x dimension to solve for acceleration but the acceleration in the y is 9.8.

You need to be clear about which coordinate (x or y) represents the horizontal direction and which represents the vertical direction.

If x represents the horizontal direction, why do you think the projectile is accelerating in that direction?

 

[dean barry]

Given that x is horizontal and y is vertical, the starting point is to break the launch velocity into its horizontal vector (x) ( which is deemed to be constant velocity )
and its vertical vector (y) which comes under the influence of gravitational deceleration.
Ive attached a sheet, which won't solve your problem but might give you a start.

 

[siddharth23]

The velocity change will only take place in the y direction. Calculate the x component of velocity and the y component after 2 seconds and find their resultant.

 

[thegoosegirl42]

You need to be clear about which coordinate (x or y) represents the horizontal direction and which represents the vertical direction.

If x represents the horizontal direction, why do you think the projectile is accelerating in that direction?

Yep thank you I was going in both.

 

[thegoosegirl42]

Given that x is horizontal and y is vertical, the starting point is to break the launch velocity into its horizontal vector (x) ( which is deemed to be constant velocity )
and its vertical vector (y) which comes under the influence of gravitational deceleration.
Ive attached a sheet, which won't solve your problem but might give you a start.

Thank you very much that helped Immensely!

 

[thegoosegirl42]

The velocity change will only take place in the y direction. Calculate the x component of velocity and the y component after 2 seconds and find their resultant.

Than you very much this made it so much easier!