Projectile motion of an arrow to an apple

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Homework Help Overview

The problem involves projectile motion, specifically calculating the launch angle of an arrow shot at an apple, given the initial speed and horizontal distance. The scenario references a historical context involving William Tell.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equations of motion for projectile motion, noting the horizontal and vertical components of the arrow's trajectory. There is uncertainty about how to determine the time of flight and the implications of the initial and final vertical positions.

Discussion Status

Some participants have provided equations related to the motion, while others express confusion about finding the time variable. There is a recognition that two equations can be used to solve for the unknowns, but no consensus on the method has been reached.

Contextual Notes

Participants note the absence of a time value, which is critical for solving the equations presented. The discussion also highlights the assumption that the arrow and apple start at the same height.

ornitho
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im having a very difficult time with this question:

William Tell is said to have shot an apple off his son's head with an arrow. If the arrow was shot with an initial speed of 55m/s and the boy was 25m away, at what launch angle did William aim the arrow? The arrow and apple are initially at the same height above the ground.
 
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x = v_{0}\cos \theta \; t
y = v_{0}\sin \theta\; t -\frac{1}{2}gt^{2}

v_{0} = 55So you have:

25 = 55\cos \theta \; t
0 = 55\sin \theta\; t - 5t^{2}
 
Last edited:
I do not have time value though :(
 
y = 0 wouldn't it, as it is returning to the initial y position, but i still do not understand how I am supposed to find t
 
The maximum altitude occurs at t = \frac{v_{0}\sin\theta}{g}.

The maximum altitude is: \frac{v_{0}^{2}}{2g}\sin^{2}\theta
 
ornitho said:
y = 0 wouldn't it, as it is returning to the initial y position, but i still do not understand how I am supposed to find t

That's right! now if you understand courtrigrad's earlier equations, for velocity and position, you have two equations, and two unknowns (t and the angle, theta). You can then solve the set of equations for both unknowns.
 
Last edited:

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