Projectile Motion of thrown ball

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Homework Help Overview

The discussion revolves around a projectile motion problem where a ball is thrown at a 45-degree angle to hit a target. The original poster explores how the time to reach the target changes when the ball is thrown at an angle that creates a trajectory with two identical bumps, assuming no loss of speed at the bounce.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the time of flight and horizontal distance for both the standard and modified trajectories. Some participants question the validity of certain steps in the calculations, particularly regarding the use of trigonometric identities and the resulting domain error.

Discussion Status

Participants are actively engaging with the calculations, identifying potential errors, and discussing the implications of those errors. There is a suggestion that a minor mistake in the calculations led to confusion, and one participant claims to have arrived at a specific angle as a solution, although this has not been universally confirmed.

Contextual Notes

There is mention of a domain error in the calculations, indicating a potential misunderstanding of the mathematical relationships involved. The problem also assumes ideal conditions, such as no loss of speed at the bounce, which may influence the discussion.

Austin Chang
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Homework Statement


A person throws a ball at a 45 degree angle and hits a given target. How much quicker does the ball get to the target if the person instead throws the ball with the same speed v0 but at the angle that makes the trajectory consist of two identical bumps, as shown (Assume unrealistically that there is no loss in speed at the bounce)

Homework Equations


x(t) = v0 cosΘ t
y(t) = v0 sin Θ t - 1/2 g t2

The Attempt at a Solution


0 = v0 sinΘ t -1/2 g t2
1/2 g t2 = v0 sinΘ t
1/2 gt = v0 sinΘ
t = 2 v0 sin Θ/ g
x = 2 v02 cosΘ sinΘ / g
x = 2 v02 cos45 sin45 / g
x= 2 v02 * .5 / g
Second ball( the one that bounces with two parabolas)
x/2 = 2v0cosΘsinΘ / g
v02 cosΘ sinΘ/g = 2 v02*.5/g
cosΘsinΘ = 1
2cosΘsinΘ = 2
sin2Θ = 2
sin-1(2) = 2θ
domain error I know why its domain error. Just don't know what went wrong in problem
 
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Austin Chang said:
x/2 = 2v0cosΘsinΘ / g
v02 cosΘ sinΘ/g = 2 v02*.5/g
Check that step. (The first line is missing a power of 2, but that's clearly just a typo, not the error I care about.)
 
haruspex said:
Check that step. (The first line is missing a power of 2, but that's clearly just a typo, not the error I care about.)
Oh lol, that was a silly mistake times 2 instead of divide by 2 Ok I got 15 degrees as an answer. Is that correct?
 
Austin Chang said:
Oh lol, that was a silly mistake times 2 instead of divide by 2 Ok I got 15 degrees as an answer. Is that correct?
Yes.
 

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