Projectile motion only provided acceleration diatance

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To determine the initial vertically upward speed and horizontal speed of a projectile, it's essential to differentiate between vertical and horizontal displacements. The vertical displacement only accounts for the distance from launch to maximum height, while the horizontal displacement covers the entire trajectory. It is crucial to recognize that only horizontal acceleration is zero, necessitating the use of equations that incorporate vertical acceleration. The discussion highlights a common misunderstanding in applying these principles to solve projectile motion problems. Accurate calculations require careful attention to these distinctions.
James1019
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TL;DR Summary: Find initial vertically upward speed of the ball
Find horizontal speed of the speed
Find angle

How to:
Find initial vertically upward speed of the ball
Find horizontal speed of the speed
Find angle
20231028_092617.jpg
i try to solve it but it didn't work
16984816945591010657629979908053.jpg
 
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1. You have mixed up vertical and horizontal displacements.
2. The given vertical displacement is from launch to max height, but the given horizontal displacement is for the whole trajectory.
3. Only the horizontal acceleration is zero. You need an equation involving vertical acceleration.
 

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