(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

(e) What is the angle made by the velocity vector with the horizontal?

A projectile is shot from the edge of a cliff h = 165 m above ground level with an initial speed of v0 = 145 m/s at an angle of 37.0° with the horizontal, as shown below:

http://img135.imageshack.us/img135/3468/projectilelaunchox5.th.jpg [Broken]http://g.imageshack.us/thpix.php [Broken]

Seconds in the air is 19.532760239244074174748994000901s

Range of total distance traveled is 2261.9356107635250879761691838034m

Final Velocity for x before it hits the ground: 115.80214895685746271118011659m/s

Final Velocity for y before it hits the ground: -104.15787198754492632443347614472m/s (upwards is positive)

Magnitude of final velocities (hypotenuse-more or less): 155.75300960174092250733936761367m/s

These are just other informations obtained throughout the problem.

2. Relevant equations

Trigonometry-sin/cos/tan

3. The attempt at a solution

Basically I used opposite divided by adjacent and then inverse tan it.

Tan θ = opp/adj

Tan θ = 165m/2261.9356107635250879761691838034m

θ = 4.172129598188136156302219438937°

Here is a picture of it, very slightly modified:

[img=http://img583.imageshack.us/img583/733/projectilelaunchangleik5.th.jpg] (the picture wont show up as image)

This did not come out as correct. If anyone can point out errors to find the correct answer, it would be appreciated.

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# Homework Help: Projectile Motion Problems- Find Angle

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