Projectile Motion Problems: Solving for Time with Given Initial Speed and Height

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Homework Help Overview

The discussion revolves around solving projectile motion problems involving time, initial speed, and height. Participants are examining two specific scenarios: one involving a projectile fired upward and another involving a ball thrown from a tower.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply kinematic equations to find the time of flight for projectiles. There are discussions about the relevance of height in the calculations and how to set up the equations correctly. Some participants express confusion about the formulas and the interpretation of variables.

Discussion Status

Several participants are sharing their attempts at solving the problems, with some providing algebraic manipulations and others questioning the assumptions made in their setups. There is a mix of progress and confusion, with guidance being offered on the need to clarify the displacement and units involved.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the amount of direct help they can receive. There is an emphasis on ensuring that the answers are in the correct units, particularly converting seconds to minutes.

Sophialiu609
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t=number of seconds
h=height
r=initial speed
How do you solve these two problems?
1. A projectile is fired upward with an initial speed of 2940 m/s. After how many minutes does it hit the ground?
2. A ball is thrown upward from the top of a 98m tower with an initial speed of 39.2 m/s. When does it hit the ground?
I don't understand how you can find the answers to these types of problems
 
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Help PLEASE!
I got this far on the second one...
h=rt- 4.9t²
-98=39.2t-4.9t²
-20=8t-t²
0=-(t²-8t -20)
0=-(t-10)(t+2)
(t-10)=0 (t+2)=0
t=10 t=-2
 
Last edited:
For the first:
If you don't need the height then why are you calculating it ?
Try Vf = Vi + at
Where t would be time of flight & Vf,Vi final and initial velocity respectively
 
Last edited:
Well, I'm supposed to put the problem into that formula, that's what I'm confused about.
 
Don't forget to convert time to minutes b/c the answer you will get is in seconds.
 
For the first, if it's fired from the ground and lands on the ground, what is h (often times, more appropriately written as \Deltah)?
 
Sophialiu609 said:
Well, I'm supposed to put the problem into that formula, that's what I'm confused about.

For the first question: you can use the same equation as you did for problem #2. If the projectile returns to the ground, what is its displacement? What does that make h in your equation?
 
Ok, so what I have so far is
0=2940t/60 -4.9t^2/60
0=-4.9t(t/60 -1)
0=-4.9t(t-1/60)
0=-4.9t(t-1)
t={0,1}
Is that right?
 
0=2940t-4.9t²
60 60
0=2940t-4.9t²
0=600t-t²
0=-t(t-600)
-t=0 (t-600)=0
t=0 t=600

or is this right?
 
  • #10
Just a little tip, you might want to work through things in algebra before you number plug :)
 
  • #11
Would time 0 make sense as an answer?

And what units are your answers in?
 
  • #12
0 wouldn't make sense as an answer, my answer is in minutes~I think... but now I'm more confused...
 
  • #13
Is it 10 minutes...?
 
  • #14
Sophialiu609 said:
Is it 10 minutes...?
Stop guessing. What equation are you using?

And before plugging values into your equation, let's SOLVE for the variable we want.
 
  • #15
The one I posted as the title!
h=rt-4.9t^2
 
  • #16
Sophialiu609 said:
The one I posted as the title!
h=rt-4.9t^2
Well looks right to me. You have it in terms of minutes, so there you go.
 
  • #17
So was my answer correct? 10 minutes? Because 600/60=10
 
  • #18
oh ohkay, thank you i didn't see the second page
 

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