A small rock is thrown upward with a speed of 30ft/s from the edge of a building 200ft above the ground. What is the speed of the rock when it hits the ground? Use acceleration due to gravity as –32ft/s squared.
integral of acceleration= v(t)
integral of v(t)= position
The Attempt at a Solution
I know that v(t)=30, the initial position is 200 and acceleration=-32 and I know the problem is asking for the velocity of the rock, I visualize this problem under the interval [a,b] so it's asking for the velocity at b when the rock hits the ground. I just have no idea how all of the information fits together to set up an integral equation. Any help with this initial set up would be great