Projectile Motion: Questions on Velocity & Height

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SUMMARY

In projectile motion, the x-component of velocity remains constant above the release point when ignoring external forces. The equation Y = Voy * t - 0.5 * 9.81 * t^2 is used to calculate the height of a projectile at any given time, assuming the initial position is zero. If the projectile is released from a height, the initial position must be included in the equation as Y = Yinitial + Voy * t - 0.5 * 9.81 * t^2, where Y represents the instantaneous position in the y-component.

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soul5
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I have 2 question.


1) In projectile motion is the velocity in the x compontent constant, while above the release point?

2) Is Y = Voy * t - 0.5 * 9.81 * t^2 the equation used to find the heigth at any given time?


Thank You.
 
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1) If you ignore any forces acting on the projectile (and for basic courses and simplicity you usually do) or consider them to be zero, then yes.

2) If your initial position is zero, then yes. In a question where a projectile is dropped from a height (one that would have a "release point") typically you would use that height as the initial position.
Edit- The "Y" would be instantaneous position in the y component. The initial "Y" would be inserted on the right side of the equation. (Y = Yinitial+ Voy*t - 0.5*9.81*t^2)
 
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