Projectile Motion: Skateboarder on a Ramp

[DRC12]

Homework Statement

A skateboarder starts up a 1.0--high, 30 ramp at a speed of 7.9 . The skateboard wheels roll without friction. How far from the end of the ramp does the skateboarder touch down?

Homework Equations

x=x₀+v₀t+.5(a)(t₂)
v=v₀+at

The Attempt at a Solution

This question seems pretty straight forward and I've found an answer but the website we use says it's wrong. First I found v_x=7.9cos(30)=6.84 and v_y=7.9sin(30)=3.95. I tried finding maximum y by solving v_y=0=-9.8*t₁ then t₁=.405 and plugging that into y=1.8 then finding t₂ when y=0 and y₀=1.8 to get t₂=.605 so t_total=1.01 and plugging that into x=6.913

 

[azizlwl]

A skateboarder starts up a 1.0--high, 30 ramp at a speed of 7.9 . The skateboard wheels roll without friction. How far from the end of the ramp does the skateboarder touch down?
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My understanding that it starts off a flat ramp top.
I do not understand whether the friction has any factor in the calculation.
With zero initial vertical velocity, in my calculation the distance from the base is 1.8m

 

[DRC12]

sorry 30 ramp is supposed to be 30^o ramp

 

[Simon Bridge]

What immediately occurs to me is that the ground (where the skateboarder touches down) is at a different height to the end of the ramp (where ballistic motion starts).
The 7.9m/s is at the bottom of the ramp, not the top.

 

[DRC12]

Yeah that was it the 7.9 was at the bottom of the ramp not the end of the ramp thanks