Projectile Motion: Understanding Vertical and Horizontal Acceleration

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A projectile fired at an angle experiences vertical acceleration of 9.8 m/s² downward, confirming it is a freely falling body. Horizontal acceleration remains zero, as it does not depend on initial speed or the angle of projection when air resistance is neglected. The discussion emphasizes the distinction between vertical and horizontal motion, clarifying that only vertical acceleration is affected by gravity. The importance of understanding these principles is highlighted for solving projectile motion problems. Overall, recognizing the independence of horizontal motion from vertical factors is crucial in analyzing projectile trajectories.
ENCJ
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Homework Statement


A projectile is fired at some angle theta to the horizontal with some initial speed vi, and air resistance is neglected. Which statements about the projectile are true? (Select all that apply.)

1.The projectile is a freely falling body.
2.Vertical acceleration is 9.8 m/s2, downward.
3.Vertical acceleration is 9.8 m/s2, upward.
4.Vertical acceleration depends on theta.
5.Horizontal acceleration is zero.
6.Horizontal acceleration depends on vi.
7.Horizontal acceleration depends on theta

Homework Equations


Vxi=vi*cos(theta)


The Attempt at a Solution


1.The projectile is a freely falling body.
2.Vertical acceleration is 9.8 m/s2, downward.
6.Horizontal acceleration depends on vi.
7.Horizontal acceleration depends on theta
 
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ENCJ said:
6.Horizontal acceleration depends on vi.

why do you think this is true?
 
Most is correct, however I think you should more on what kind of acceleration affects horizontal movement if air resistance is neglected. There are 4 correct alternatives though.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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