Projectile problem: A block released from a balloon

  • Thread starter Thread starter AnishaTabassum
  • Start date Start date
Click For Summary
The discussion revolves around a physics problem involving a block released from a balloon after being hit by a bullet. Participants emphasize the need for clarity regarding the balloon's velocity direction and the interpretation of the block's fall angle and speed. Concerns are raised about the excessive horizontal speed of 200 m/s for the block and the vagueness of the problem statement. The importance of adhering to homework guidelines and demonstrating prior effort in solving the problem is also highlighted. Overall, the thread underscores the necessity for precise information to effectively tackle the physics question.
AnishaTabassum
Messages
1
Reaction score
0
New PF user has been reminded to always show their work on schoolwork problems.
Homework Statement
A block is placed on a balloon and released. The balloon has a velocity of 12 m/s and is hit by a bullet, which makes the block fall at an angle of 30° with the horizontal with a velocity of 200 m/s. The block falls to the ground 12 s after the impact. How high was the balloon above the ground when the bullet hit the block?What is the maximum height the block will rise to?
Relevant Equations
h=ut-1/2gt^2
v^2=u^2-2gh
I can't solve this problem. Please someone help me with it.
 
Physics news on Phys.org
According to our rules, to receive help, you need to show some credible effort towards answering the question. How about telling us what you do know and how you would approach this problem?

Please read, understand and follow our homework guidelines, especially item 4, here

 
  • Like
Likes TensorCalculus
You might also want to move this to the Introductory Physics Homework help thread too, since it doesn't look like a graduate-level problem. If people are looking to help with problems like this one that's generally where they'll head :)
 
AnishaTabassum said:
Homework Statement: A block is placed on a balloon and released. The balloon has a velocity of 12 m/s and is hit by a bullet, which makes the block fall at an angle of 30° with the horizontal with a velocity of 200 m/s. The block falls to the ground 12 s after the impact. How high was the balloon above the ground when the bullet hit the block?What is the maximum height the block will rise to?
Relevant Equations: h=ut-1/2gt^2
v^2=u^2-2gh

I can't solve this problem. Please someone help me with it.
A horizontal speed of 200m/s seems excessive for a "block". That said, who cares?
 
PeroK said:
A horizontal speed of 200m/s seems excessive for a "block". That said, who cares?
That's the least of one's worries. We are given the velocity of the balloon as 12 m/s. What is the direction of that velocity? Balloons are known to be tossed around by winds and we are not specifically told that the balloon is ascending vertically.

Also, the passage "which makes the block fall at an angle of 30° with the horizontal with a velocity of 200 m/s. The block falls to the ground 12 s after the impact." needs interpretation.
  • Is the "angle of 30° with the horizontal" above or below the horizontal?
  • If "above the horizontal", are the values of 30° and 200 m/s appropriate to the time when the block is hit by the bullet or the time when it lands on the ground?
 
  • Like
Likes PeroK and Lnewqban
It looks like one of those questions where someone who knows very little physics has thrown some numbers into a vague problem statement.
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

Similar threads

  • · Replies 3 ·
Replies
3
Views
751
Replies
9
Views
1K
  • · Replies 5 ·
Replies
5
Views
958
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
627
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 38 ·
Replies
38
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 52 ·
2
Replies
52
Views
3K