Projectile problem: A block released from a balloon

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The discussion revolves around a physics problem involving a block released from a balloon after being hit by a bullet. Participants emphasize the need for clarity regarding the balloon's velocity direction and the interpretation of the block's fall angle and speed. Concerns are raised about the excessive horizontal speed of 200 m/s for the block and the vagueness of the problem statement. The importance of adhering to homework guidelines and demonstrating prior effort in solving the problem is also highlighted. Overall, the thread underscores the necessity for precise information to effectively tackle the physics question.
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New PF user has been reminded to always show their work on schoolwork problems.
Homework Statement
A block is placed on a balloon and released. The balloon has a velocity of 12 m/s and is hit by a bullet, which makes the block fall at an angle of 30° with the horizontal with a velocity of 200 m/s. The block falls to the ground 12 s after the impact. How high was the balloon above the ground when the bullet hit the block?What is the maximum height the block will rise to?
Relevant Equations
h=ut-1/2gt^2
v^2=u^2-2gh
I can't solve this problem. Please someone help me with it.
 
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According to our rules, to receive help, you need to show some credible effort towards answering the question. How about telling us what you do know and how you would approach this problem?

Please read, understand and follow our homework guidelines, especially item 4, here

 
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You might also want to move this to the Introductory Physics Homework help thread too, since it doesn't look like a graduate-level problem. If people are looking to help with problems like this one that's generally where they'll head :)
 
AnishaTabassum said:
Homework Statement: A block is placed on a balloon and released. The balloon has a velocity of 12 m/s and is hit by a bullet, which makes the block fall at an angle of 30° with the horizontal with a velocity of 200 m/s. The block falls to the ground 12 s after the impact. How high was the balloon above the ground when the bullet hit the block?What is the maximum height the block will rise to?
Relevant Equations: h=ut-1/2gt^2
v^2=u^2-2gh

I can't solve this problem. Please someone help me with it.
A horizontal speed of 200m/s seems excessive for a "block". That said, who cares?
 
PeroK said:
A horizontal speed of 200m/s seems excessive for a "block". That said, who cares?
That's the least of one's worries. We are given the velocity of the balloon as 12 m/s. What is the direction of that velocity? Balloons are known to be tossed around by winds and we are not specifically told that the balloon is ascending vertically.

Also, the passage "which makes the block fall at an angle of 30° with the horizontal with a velocity of 200 m/s. The block falls to the ground 12 s after the impact." needs interpretation.
  • Is the "angle of 30° with the horizontal" above or below the horizontal?
  • If "above the horizontal", are the values of 30° and 200 m/s appropriate to the time when the block is hit by the bullet or the time when it lands on the ground?
 
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It looks like one of those questions where someone who knows very little physics has thrown some numbers into a vague problem statement.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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