Projectile Problem: Find Theta | d=30, v=22, g=9.8, y0=2

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SUMMARY

The discussion focuses on solving a projectile motion problem where the launch point is higher than the target point. Given parameters include a target distance (d) of 30 meters, an initial velocity (v) of 22 m/s, gravitational acceleration (g) of 9.8 m/s², and a launch height (y0) of 2 meters. The key to finding the launch angle (theta) involves analyzing the motion along the x- and y-axes separately, as suggested by the referenced Wikipedia article on projectile range on uneven ground.

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Homework Statement



Hi to all guys i am not good in physics and trigonometric I tried to do a projectile system.My launch point is higher than target point.I know the velocity v, target_distance d, gravity g,Launch_height_y y0.I added a image that shows the equation.I tried my own but not solved the equation.Please some one help me

d = 30,v = 22 , g = 9.8 ,y0 = 2

I wants to find the theta(angle)

Homework Equations





The Attempt at a Solution

 

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Not sure how you got the equation but ut would be best to analyse along the independent x- and y-axes.One is accelerated and other is simple non-accelerated one.
 
Of course it is right. What I meant was analysis along x- and y-axes separately is much simpler(that's how they got the formula).
 

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