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## Homework Statement

An object is thrown into the air from the ground at an angle of 35deg to the horizontal. If this object is in the air for 9.26 s, at what velocity was it thrown?

## Homework Equations

vf^2=vi^2+2ad

d=vit +1/2at^2

d=v/t

a=vf-vi/t

## The Attempt at a Solution

x motion

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vi=vf because no acceleration

t=9.26 s

a=0

y motion

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a= -9.8

t=9.26

d=419.7m

vf=90.7m/s

vi=0

I arrived at vertical distance by the following:

90.7^2 = 0 + 2(-9.8)d

d=419.7

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I arrived at final vertical velocity by the following:

-9.8=vf-0/9.26

vf=90.7m/s

I don't know if these are correct values or not, but even if they are...i don't know how they arrived at the final answer of 79.1m/s. Please help?