- #1

posto002

- 26

- 5

- Homework Statement
- A system of inertia 0.59 kg consists of a spring gun attached to a cart and a projectile. The system is at rest on a horizontal low-friction track. A 0.050-kg projectile is loaded into the gun, then launched at an angle of 40∘ with respect to the horizontal plane. With what speed does the cart recoil if the projectile rises 2.1 m at its maximum height?

- Relevant Equations
- vf^2=vi^2+2ad

Conservation of momentum

I started off with vf^2=vi^2+2ad and plugged in the final velocity, acceleration (9.8) and distance which is 2.1 to get:

0=vi^2+2(9.8)(2.1) I solved this to get:

vi=6.42

I then plugged this into find the x-component of vi (I labeled this as simply x):

tan(40degrees)=6.42/(x) Solving for x I get:

x=7.65

After solving for the x-component, I use the conservation of momentum to produce:

0.59v=0.05(7.65)

0.59v=0.3825

v=0.65m/s for the speed that the object recoils, but that answer is incorrect. Can someone help me see what I did wrong? Thank you!

0=vi^2+2(9.8)(2.1) I solved this to get:

vi=6.42

I then plugged this into find the x-component of vi (I labeled this as simply x):

tan(40degrees)=6.42/(x) Solving for x I get:

x=7.65

After solving for the x-component, I use the conservation of momentum to produce:

0.59v=0.05(7.65)

0.59v=0.3825

v=0.65m/s for the speed that the object recoils, but that answer is incorrect. Can someone help me see what I did wrong? Thank you!