Projectile problem with no angles

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SUMMARY

The projectile problem involves a horizontal launch from a height of 53.0 meters with a muzzle velocity of 235 m/s. The key to solving this problem lies in recognizing that the launch angle is 0 degrees, indicating a purely horizontal trajectory. To determine the time the projectile remains in the air, one must calculate the time it takes to fall 53.0 meters under the influence of gravity, which is approximately 3.3 seconds.

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of gravitational acceleration (9.81 m/s²)
  • Familiarity with basic kinematic equations
  • Ability to interpret horizontal and vertical components of motion
NEXT STEPS
  • Calculate the time of flight for different heights using the formula \( t = \sqrt{\frac{2h}{g}} \)
  • Explore the effects of varying launch angles on projectile motion
  • Learn about the range and maximum height of projectiles launched at angles
  • Investigate real-world applications of projectile motion in sports and engineering
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in understanding the dynamics of horizontal projectile launches.

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A projectile is fired horizontally from a gun that is 53.0 m above flat ground. The muzzle velocity is 235 m/s. How long does the projectile remain in the air?

All of the practice problems in my book are given an angle to work with. For some reason I'm having a hard time starting this problem because I'm under the impression that I need to find an angle but I feel like I don't have enough information. Any help to point me in the right direction is greatly appreciated.
 
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you still have an initial angle. It is just 0 degrees from the horizontal axis.
 
Which means it is falling out of "rest" downwards.
 

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