Projectile Problem: Horizontal Velocity Analysis

  • Thread starter Shahab Mirza
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In summary, the graph represents the horizontal velocity component (Vx) versus time for a projectile thrown horizontally off a cliff without considering air resistance. The graph is labeled incorrectly as Vy versus Vx and should be Vx versus time. Since Vx is constant, the graph should show a horizontal line, indicating that the velocity remains the same as time increases. This is because there is no acceleration in the horizontal direction.
  • #1
Shahab Mirza
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The following graph (ATTACHED) represents the horizontal velocity component (Vx) verses time for a projectile thrown horizontally off a cliff. (Ignored Air resistance) .
But I thought that graph will be a 45 degree slope straight line , because Horizontal component of velocity of projectile remains constant because there is no acceleration in horizontal direction , then why graph is like that any idea please ? Thanks
 

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  • #2
Shahab Mirza said:
The following graph (ATTACHED) represents the horizontal velocity component (Vx) verses time for a projectile thrown horizontally off a cliff. (Ignored Air resistance) .
Looks like the axes are mislabeled as Vy versus Vx. It should be Vx versus time. Because Vx is constant the graph will be a horizontal line, as shown.
 
  • #3
Doc Al said:
Looks like the axes are mislabeled as Vy versus Vx. It should be Vx versus time. Because Vx is constant the graph will be a horizontal line, as shown.
ops sorry , it is VX versus time , yes now explain how graph is horizontal line ?
 
  • #4
In this graph of Vx vs time, Vx is along y-axis and t is along x-axis, now the y-axis is cut on only one point, this signifies that its value will remain constant or same(equal to y coordinate of that point) even if time is increasing. Thats why it is represented as a horizontal line parallel to time axis. The graph line is increasing along the time axis only(horizontally) there is no vertical displacement in the graph line which signifies as time increases the y coordinate i.e Vx is same.
 

FAQ: Projectile Problem: Horizontal Velocity Analysis

1. What is a projectile problem?

A projectile problem is a type of physics problem that involves analyzing the motion of an object that is launched into the air, such as a ball or a bullet. These problems typically involve calculating the object's initial velocity, angle of launch, and its trajectory.

2. What is horizontal velocity?

Horizontal velocity is the component of an object's velocity that is parallel to the ground. In projectile problems, the horizontal velocity remains constant throughout the object's motion, assuming there is no air resistance.

3. How do you calculate horizontal velocity?

To calculate horizontal velocity, you can use the formula: vx = v * cosθ, where vx is the horizontal velocity, v is the magnitude of the initial velocity, and θ is the angle of launch.

4. How does horizontal velocity affect the motion of a projectile?

Horizontal velocity does not affect the vertical motion of a projectile, but it does affect the horizontal motion. The higher the horizontal velocity, the farther the object will travel before hitting the ground.

5. What are some real-world applications of projectile problems?

Projectile problems have many real-world applications, such as in sports, military operations, and engineering. For example, in sports like baseball and basketball, players must understand projectile motion to accurately shoot or throw a ball. In military operations, projectile problems are used to calculate the trajectory of missiles and projectiles. In engineering, projectile problems are used to design and test structures and machines that launch objects into the air.

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