Projectile Velocity: Vx & Accel at Highest Point?

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At the highest point of a projectile's trajectory, the vertical component of velocity (Vy) is zero, while the horizontal component (Vx) remains equal to the initial horizontal velocity. The acceleration due to gravity acts constantly on the projectile throughout its flight, affecting only the vertical motion. Therefore, the velocity at the highest point is determined solely by the initial horizontal velocity. The horizontal motion is unaffected by gravity, confirming that Vx does not change. Understanding these principles is essential for analyzing projectile motion accurately.
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Hey, I had a basic conception question about projectile velocity. When a projectile reaches its highest point, does the velocity of the projectile equal 0 or does it equal the initial x velocity? I know that Vy=0 at the highest point of a projectile's trajectory, but I'm not sure about the other component(s). Does this also go for the acceleration of the projectile?
 
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When a projectile reaches its highest point you are correct in that its y component of velocity is zero. The x component however is unchanged. A projectile will be subject to a constant acceleration due to gravity.
 
Does that mean that the velocity of a projectile at the highest point of its trajectory will be whatever the initial X velocity is?
 
Yes. The acceleration is always constant.
 
Thanks.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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