Projectile with fixed angle and tripled velocity

[enantiomer1]

Homework Statement

Hi, I'm stuck on this problem (it seems simple but I can't seem to get it down),
The question is, "A certain cannon with a fixed angle of projection has a range of 1500 m. What will be its range if you add more powder so that the initial speed of the cannonball is tripled?"

Homework Equations

d=v_hori*t
d=v_hori cos theta * t

The Attempt at a Solution

At first I simply saw this as a distance versus velocity and time problem (x=v_0x*t so I simply tripled the distance getting 4500; not surprisingly, I was wrong. I'm sure that the equation relies on the 'fixed angle' part of the equation so I simply divided the equation by 2^1/2 (due to cos theta) getting 3192, but I'm still wrong, what variable am I forgetting?

 

[LowlyPion]

Welcome to PF.

If you triple the speed, what do you do to the horizontal velocity?

What does tripling the speed do to the time to max height and back down?

Distance is v * t so ...