Projection matrix onto a subspace

[cheertcc101]

Alright so I am trying to find the projection matrix for the subspace spanned by the vectors

[1] and [2]
[-1] [0]
[1] [1]

I actually have the solution to the problem, it is ...

P = [ 5 1 2 ]
(1/6) [1 5 -2]
[2 -2 2]

Every formula I have found is not for two vectors but a vector and a matrix or something else. I found the formula P = A(A^TA)^-1A^T but that makes no sense for what A could be since I'm given two vectors and not a matrix. I feel like I'm missing something simple.

PLEASE help!

Thanks

 

[HallsofIvy]

The vectors <1, -1, 1> and <2, 0, 1> are independent so there exist a third vector, independent of both and all 3 form a basis for R³. It should not be hard for you to find such a third vector. Then you want a matrix that maps <1, -1, 1> and <2, 0, 1> to themselves and the third vector to <0, 0, 0>. that gives you 9 equations to solve for the 9 numbers in the matrix. Actually they separate into 3 sets of 3 equations.