Proof including a one to one function

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If f(x) is a one-to-one function, then g(x) = f(x^3) is also one-to-one. The reasoning involves the definition of injective functions, where each element in the range corresponds to at most one element in the domain. The transformation x^3 retains the one-to-one property since it is a strictly increasing function. Therefore, if g(a) = g(b), it implies that a must equal b, confirming that g is injective. The conclusion is that the composition of a one-to-one function with another one-to-one function preserves the one-to-one property.
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Homework Statement



if f(x) is a one-to-one function, then g(x) = f(x^3) is also a one-to-one function

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The Attempt at a Solution



Assume f(x) is a one to one function. For a particular element of B, there is at most one element of A which is mapped to it. Therefore, by the definition of injective x^3 must also be one to one.

This is what I have, but I don't think that this is the way to go about it.
 
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